Warning: copy(..): failed to open stream: No such file or directory in
copy, file-upload, php, stream, upload
Solution
make sure that the destination directory exists, copy will not create directories for you.
The 2nd parameter is for file permissions and important for security, read more: https://wiki.archlinux.org/index.php/File_permissions_and_attributes
The 3rd parameter will also create recursive directories.
if (!is_dir($directory)) {
mkdir($directory, 0777, true);
}
Problem
I'm fairly new to PHP and was trying to create a simple PHP file upload system. I followed a tutorial from (http://www.phpeasystep.com/phptu/2.html). I only altered the `$HTTP_POST_FILES`, as it was giving me errors, and from what I read it's old in PHP. I got less error messages but I am getting an error in the `copy()` function, with these given error messages: ``` Warning: copy(Task2/uploads/anonymous.jpg): failed to open stream: No such file or directory in C:\xampp\htdocs\Task2\upload.php on line 13 Warning: copy(Task2/uploads/DSCF4639.JPG): failed to open stream: No such file or directory in C:\xampp\htdocs\Task2\upload.php on line 14 Warning: copy(Task2/uploads/jien maroon.jpg): failed to open stream: No such file or directory in C:\xampp\htdocs\Task2\upload.php on line 15 ``` I thought it was a problem with permission (read/write permissions in Windows 7), but from a quick google search it seems that XAMPP is set by default to deal with permission on Win 7. This is the code: ``` <?php //set where you want to store files //in this example we keep file in folder upload //$_FILES['ufile']['name']; = upload file name //for example upload file name cartoon.gif . $path will be upload/cartoon.gif $path1= "Task2/uploads/".$_FILES['ufile']['name'][0]; $path2= "Task2/uploads/".$_FILES['ufile']['name'][1]; $path3= "Task2/uploads/".$_FILES['ufile']['name'][2]; //copy file to where you want to store file copy($_FILES['ufile']['tmp_name'][0], $path1); copy($_FILES['ufile']['tmp_name'][1], $path2); copy($_FILES['ufile']['tmp_name'][2], $path3); //$_FILES['ufile']['name'] = file name //$_FILES['ufile']['size'] = file size //$_FILES['ufile']['type'] = type of file echo "File Name :".$_FILES['ufile']['name'][0]."<BR/>"; echo "File Size :".$_FILES['ufile']['size'][0]."<BR/>"; echo "File Type :".$_FILES['ufile']['type'][0]."<BR/>"; echo "<img src=\"$path1\" width=\"150\" height=\"150\">"; echo "<P>"; echo "File Name :".$_FILES['ufile']['name'][1]."<BR/>"; echo "File Size :".$_FILES['ufile']['size'][1]."<BR/>"; echo "File Type :".$_FILES['ufile']['type'][1]."<BR/>"; echo "<img src=\"$path2\" width=\"150\" height=\"150\">"; echo "<P>"; echo "File Name :".$_FILES['ufile']['name'][2]."<BR/>"; echo "File Size :".$_FILES['ufile']['size'][2]."<BR/>"; echo "File Type :".$_FILES['ufile']['type'][2]."<BR/>"; echo "<img src=\"$path3\" width=\"150\" height=\"150\">"; /////////////////////////////////////////////////////// // Use this code to display the error or success. $filesize1=$_FILES['ufile']['size'][0]; $filesize2=$_FILES['ufile']['size'][1]; $filesize3=$_FILES['ufile']['size'][2]; if($filesize1 && $filesize2 && $filesize3 != 0) { echo "We have recieved your files"; } else { echo "ERROR....."; } ////////////////////////////////////////////// // What files that have a problem? (if found) if($filesize1==0) { echo "There're something error in your first file"; echo "<BR />"; } if($filesize2==0) { echo "There're something error in your second file"; echo "<BR />"; } if($filesize3==0) { echo "There're something error in your third file"; echo "<BR />"; } ?> ``` Any help would be appreciated ! Thanks !