Why my copy constructor not called?

Possible Duplicate: What are copy elision and return value optimization? I have the following program: ``` #include <iostream> using namespace std; class Pointt { public: int x; int y; Pointt() { x = 0; y = 0; cout << "def constructor called" << endl; } Pointt(int x, int y) { this->x = x; this->y = y; cout << "constructor called" << endl; } Pointt(const Pointt& p) { this->x = p.x; this->y = p.y; cout << "copy const called" << endl; } Pointt& operator=(const Pointt& p) { this->x = p.x; this->y = p.y; cout << "op= called" << endl; return *this; } }; Pointt func() { cout << "func: 1" << endl; Pointt p(1,2); cout << "func: 2" << endl; return p; } int main() { cout << "main:1" << endl; Pointt k = func(); cout << "main:2" << endl; cout << k.x << " " << k.y << endl; return 0; } ``` The output I expect is the following: ``` main:1 func: 1 constructor called func: 2 copy const called op= called main:2 1 2 ``` But I get the following: ``` main:1 func: 1 constructor called func: 2 main:2 1 2 ``` The question is: why doesn't returning an object from func to main call my copy constructor?