Question regarding pointers in fscanf

Question

I am using C. I am having issues with using pointers for the fscanf function. When I try to do: ``` int *x; /* ... */ fscanf(file, "%d", x[i]); ``` My compiler gives me a warning saying "format argument is not a pointer" and the code just doesn't run (I get a message saying "Water.exe has stopped working"). If I replace x with *x, it just doesn't compile... Is this just a syntax issue?

Accepted Answer

If you want to read a single integer, do this:

```
int x;
fscanf(file, "%d", &x );
```

If you want, you could do this to read a single integer in a dynamically-allocated variable:

```
int *x = malloc(sizeof(int));
fscanf(file, "%d", x );
```

If you want an array of integers, do this:

```
int *x = malloc(sizeof(int) * DESIRED_ARRAY_SIZE);
fscanf(file, "%d", &x[i] );
```

`%d` expects a pointer to an `int`, but `x[i]` is an `int`, so you need to take the address of your list element using the address-of operator (unary `&`).

Question regarding pointers in fscanf

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