Command line current working directory in a console app
c#, console, windows
Solution
Environment.CurrentDirectory gives you the Current Working Directory
Let me show a simple example:
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Startup: " + Environment.CurrentDirectory);
Environment.CurrentDirectory = @"D:\temp";
Console.WriteLine("After:" + Environment.CurrentDirectory);
}
}
Now I create two folders named `D:\temp` and `D:\temp2` I put the executable in `D:\temp` Open a command prompt and set the current working directory with `cd D:\temp2` From that directory I run `..\temp\mytestapp.exe`
the output is
Startup: D:\temp2
After: D:\temp
As a curiosity:
this was the documentation for Environment.CurrentDirectory in Net 1.1
Gets and sets the fully qualified path of the current directory; that is, the directory from which this process starts.
and this is the documentation in NET 4.0
Gets or sets the fully qualified path of the current working directory.
Problem
Possible Duplicate: How do I find out what directory my console app is running in with C#? How to get current working directory of a console that runs a program so I could resolve relative paths passed as program args? Lets say I've put my program here: `c:\tools\program.exe` But I'm invoking it from various places. Lets say I'm here: `C:\Users\Me\Documents\` and I run this command `program.exe --src=somefile.txt --dest=subdir\otherfile.txt` `Environment.CurrentDirectory` and `System.Reflection.Assembly.GetExecutingAssembly().Location` will return `c:\tools` but I would like to be able to resolve `somefile.txt` and `subdir\oterfile.txt` paths that are relative to `C:\Users\Me\Documents\`. ====== UPDATE ====== Thank you for your help. It seems that `Environment.CurrentDirectory` works as expected. It turned out that in my case the problem was caused by Xenocode's Postbuild tool (now called Spoon Virtual Application Studio) that I occasionally use to "pack" all program's files (including dlls, config, etc.) into one executable. It's very handy, but in this case the "virtualization" feature messed up my program's `Environment` variables. I've managed to solve that issue.