How to use symbolic group name using re.findall()

Question

Is it possible to access the symbolic group name defined in a regular expression with `(?P...)` with the equivalent of `re.findall()`? Using `re.match()`, re returns a `MatchObject` on which the function `.group('toto')` can be used... I would like to do something close. Here is an example : ``` import re my_str = 'toto=1, bip=xyz, toto=15, bip=abu' print re.findall('toto=(?P\d+)\,\sbip=(?P\w+)', my_str) ``` It returns : ``` [('1', 'xyz'), ('15', 'abu')] ``` I would like to get something like : ``` [{'toto':'1', 'bip':'xyz'}, {'toto':'15', 'bip':'abu'}] ``` Is there any simple way to do that? I can't find it anywhere...

Accepted Answer

You can't do that with `.findall()`. However, you can achieve the same effect with `.finditer()` and some list comprehension magic: ``` print [m.groupdict() for m in re.finditer('toto=(?P\d+)\,\sbip=(?P\w+)', my_str)] ``` This prints: ``` [{'toto': '1', 'bip': 'xyz'}, {'toto': '15', 'bip': 'abu'}] ``` So we loop over each match yielded by `.finditer()` and take it's `.groupdict()` result.

How to use symbolic group name using re.findall()

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