How to get multiple class in one query using Beautiful Soup

beautifulsoup, html-parsing, python

Solution

You can do this using beautiful soup's support for regular expressions.

import re
soup = BeautifulSoup(urllib2.urlopen(url).read(),"lxml");
for item in soup.find_all("td", { "class" : re.compile(r"^(s|sb)$") })

This regular expression matches:

`^` - the start of the string

`(s|sb)` - either the string `'s'` or the string `'sb'`

`$` - the end of the string

Problem

I want to find td with class="s" or class="sb" in the following html ``` <tr bgcolor="#e5e5f3"><td class="sb" width="200" align="left">test1</td><td class="sb" align="right">5,774.0</td><td class="sb" align="right">4,481.0</td><td class="sb" align="right">5,444.0</td><td class="sb" align="right">6,615.0</td><td class="sb" align="right">6,858.0</td></tr> <tr bgcolor="#f0f0E7"><td class="s" width="200" align="left">test2</td><td class="s" align="right">5,774.0</td><td class="s" align="right">4,481.0</td><td class="s" align="right">5,444.0</td><td class="s" align="right">6,615.0</td><td class="s" align="right">6,858.0</td></tr> ``` I'm using the following code right now. But can only get class equal "S". Is it possible to get both "s" and "sb" in one Beautiful Soup find_all query? ``` soup = BeautifulSoup(urllib2.urlopen(url).read(),"lxml"); for item in soup.find_all("td", { "class" : "s" }): ```

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