How to save cropped image to a directory with Jcrop using PHP

directory, image, jcrop, php, save

Solution

I am going to reply to what seems to be the question now:

But i have to make a function who can save multiple files with each another name. and maybe overwrite the original image, who is saved in 'uploads/'

An easy method to do this would be to add the timestamp in the filename, this way everytime the operation is executed, you get a new filename. Doing something along the lines of:

imagejpeg($dst_r, 'uploads/cropped/' . $filename . time() . 'boek.jpg');

Will save a new image everytime.

When you want to overwrite the original, simply assign the right path

imagejpeg($dst_r, 'uploads/' . $filename .'.jpg');

Edit: What seems to be the problem is getting the right file name, without hardcoding 'boek.jpg'.

The original code posted used the string `filename` when saving the image

imagejpeg($dst_r, 'uploads/cropped/' . 'filename');

What you want to do, is deduce the filename from `$src`. To do so, simply use the function `basename` (documentation here), so you will have:

imagejpeg($dst_r, 'uploads/cropped/' . basename($src)); // basename will already contain the extension

Problem

I can crop my images and click on crop. but then something goes wrong, because i don't know exactly how to save this image. I use imagecreatefromjpeg from php. this code look like this: ``` <?php SESSION_start(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { $targ_w = 200; $targ_h = 400; $jpeg_quality = 90; $src = $_SESSION['target_path']; $img_r = imagecreatefromjpeg($src); $dst_r = ImageCreateTrueColor( $targ_w, $targ_h ); imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'], $targ_w,$targ_h,$_POST['w'],$_POST['h']); //header('Content-type: image/jpeg'); imagejpeg($dst_r, 'uploads/cropped/' . 'filename'); exit; } ?> ``` My php code for saving the original image looks like this: ``` <?php session_start(); $target = "uploads/"; $target = $target . basename( $_FILES['filename']['name']) ; $_SESSION['target_path'] = $target; $ok=1; if(move_uploaded_file($_FILES['filename']['tmp_name'], $target)) { echo "De afbeelding *". basename( $_FILES['filename']['name']). "* is geupload naar de map 'uploads'"; } else { echo "Sorry, er is een probleem met het uploaden van de afbeelding."; } ?> ``` how do i save the cropped image? and is there a way to save the cropped image by overwriting the original so i get only the cropped image? thanks in advance. EDIT: I can save 1 photo now. i edited my code to: imagejpeg($dst_r, 'uploads/cropped/' . $filename .'boek.jpg'); But i have to make a function who can save multiple files with each another name. and maybe overwrite the original image, who is saved in 'uploads/'

Original source