Getting Django debug information when using Ajax call?
django, jquery
Solution
You can inspect the contents of the response returned to your jQuery ajax call. Using a tool like Firebug can make this pretty easy.
Django will still return the debug page, it's just that it is responding to the ajax call rather than a regular browser request.
It's often a good technique to get your stuff working with regular requests, and then "ajaxify" them only once you are sure the server side code is working.
Problem
Is there a good way to get the debug information that Django provides when using jQuery to make Ajax calls? Right now when I make a call, I just see a http/200 server error in the python runserver window, but because the call is made through javascript, I don't get a debug page with all the information.