Sort array containing objects based on another array

arrays, javascript, sorting

Solution

Here's my take on it:

function orderArray(array_with_order, array_to_order) {
    var ordered_array = [], 
        len = array_to_order.length,
        len_copy = len,
        index, current;

    for (; len--;) {
        current = array_to_order[len];
        index = array_with_order.indexOf(current.key);
        ordered_array[index] = current;
    }

    //change the array
    Array.prototype.splice.apply(array_to_order, [0, len_copy].concat(ordered_array));
}

Sample implementation:

var array_with_order = ['one', 'four', 'two'],

    array_to_order = [
        {key: 'one'},
        {key: 'two'},
        {key: 'four'}
    ];

orderArray(array_with_order, array_to_order);

console.log(array_to_order); //logs [{key: 'one'}, {key: 'four'}, {key: 'two'}];

The usual fiddle: http://jsfiddle.net/joplomacedo/haqFH/

Problem

Possible Duplicate: JavaScript - Sort an array based on another array of integers Javascript - sort array based on another array If I have an array like this: ``` ['one','four','two'] ``` And another array like this: ``` [{ key: 'one' },{ key: 'two' },{ key: 'four' }] ``` How would I sort the second array so it’s `key` property follows the order of the first? In this case, I want: ``` [{ key: 'one' },{ key: 'four' },{ key: 'two' }] ```

Original source

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