Java: println with char array gives gibberish

arrays, char, java, output

Solution

When you say

System.out.println(b);

It results in a call to `print(char[] s)` then `println()`

The JavaDoc for `print(char[] s)` says:

Print an array of characters. The characters are converted into bytes according to the platform's default character encoding, and these bytes are written in exactly the manner of the write(int) method.

So it performs a byte-by-byte print out.

When you say

System.out.println("char[] b: " + b);

It results in a call to `print(String)`, and so what you're actually doing is appending to a `String` an `Object` which invokes `toString()` on the `Object` -- this, as with all `Object` by default, and in the case of an `Array`, prints the value of the reference (the memory address).

You could do:

System.out.println("char[] b: " + new String(b));

Note that this is "wrong" in the sense that you're not paying any mind to encoding and are using the system default. Learn about encoding sooner rather than later.

Problem

Here's the problem. This code: ``` String a = "0000"; System.out.println(a); char[] b = a.toCharArray(); System.out.println(b); ``` returns ``` 0000 0000 ``` But this code: ``` String a = "0000"; System.out.println("String a: " + a); char[] b = a.toCharArray(); System.out.println("char[] b: " + b); ``` returns ``` String a: 0000 char[] b: [C@56e5b723 ``` What in the world is going on? Seems there should be a simple enough solution, but I can't seem to figure it out.

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