Android ListView understanding

android, android-listview

Solution

The layout resource id you're supposed to pass to ArrayAdapter is a layout that's used to render each item in the list, not the layout for the list itself. Android provides some layout resources for the common cases. Try using:

ArrayAdapter<String> myArrayAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, strings);

Problem

I have a question about the ListView and how to use it. My Prolem is that my listView is only a part of the view and I am not sure how to do this. ``` public class MainActivity extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ListView myListView = (ListView) findViewById(R.id.ListView01); String[] strings = new String[]{"Test1","Test2"}; ArrayAdapter<String> myArrayAdapter= new ArrayAdapter<String>(this, R.id.ListView01,strings); myListView.setAdapter(myArrayAdapter); ``` I think the problem is the "this" in myArrayAdapter!?

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