Enumerable.Repeat with Union and Take does not return 'Take' values

c#, ienumerable, linq

Solution

The reason is that `Enumerable.Union` removes duplicates. So you may want to use `Enumerable.Concat` instead which dsoesn't remove duplicates.

Another option i would prefer is to use `Enumerable.ElementAtOrdefault` to select the elements from an index created by `Enumerable.Range` where the second argument is the desired count:

IEnumerable<int> values = Enumerable.Range(0, 5)
            .Select(i => list.ElementAtOrDefault(i))
            .OrderByDescending(i => i);

Problem

Very simple problem. I have a list of values which I want to pad out with empty values such that I always have X number of items returned. ``` List<int> list = new List<int>() { 10, 20, 30 }; IEnumerable<int> values = list .OrderByDescending( i => i ) .Union( Enumerable.Repeat( 0 , 5 ) ); foreach (var item in values.Take(5)) Console.Write( item + " "); ``` I would expect an output like "30 20 10 0 0 " But surprisingly I only get "30 20 10 0". ``` foreach (var i in Enumerable.Repeat( 0, 5 ).Take(3)) Console.Write( i + " " ); ``` This code will return "0 0 0 ". Likewise "`list.Take(3)`" returns "30 20 10 ".

Original source