Replacing blank values (white space) with NaN in pandas
dataframe, pandas, python
Solution
I think `df.replace()` does the job, since pandas 0.13:
df = pd.DataFrame([
[-0.532681, 'foo', 0],
[1.490752, 'bar', 1],
[-1.387326, 'foo', 2],
[0.814772, 'baz', ' '],
[-0.222552, ' ', 4],
[-1.176781, 'qux', ' '],
], columns='A B C'.split(), index=pd.date_range('2000-01-01','2000-01-06'))
# replace field that's entirely space (or empty) with NaN
print(df.replace(r'^\s*$', np.nan, regex=True))
Produces:
A B C
2000-01-01 -0.532681 foo 0
2000-01-02 1.490752 bar 1
2000-01-03 -1.387326 foo 2
2000-01-04 0.814772 baz NaN
2000-01-05 -0.222552 NaN 4
2000-01-06 -1.176781 qux NaN
As Temak pointed it out, use `df.replace(r'^\s+$', np.nan, regex=True)` in case your valid data contains white spaces.
Problem
I want to find all values in a Pandas dataframe that contain whitespace (any arbitrary amount) and replace those values with NaNs. Any ideas how this can be improved? Basically I want to turn this: ``` A B C 2000-01-01 -0.532681 foo 0 2000-01-02 1.490752 bar 1 2000-01-03 -1.387326 foo 2 2000-01-04 0.814772 baz 2000-01-05 -0.222552 4 2000-01-06 -1.176781 qux ``` Into this: ``` A B C 2000-01-01 -0.532681 foo 0 2000-01-02 1.490752 bar 1 2000-01-03 -1.387326 foo 2 2000-01-04 0.814772 baz NaN 2000-01-05 -0.222552 NaN 4 2000-01-06 -1.176781 qux NaN ``` I've managed to do it with the code below, but man is it ugly. It's not Pythonic and I'm sure it's not the most efficient use of pandas either. I loop through each column and do boolean replacement against a column mask generated by applying a function that does a regex search of each value, matching on whitespace. ``` for i in df.columns: df[i][df[i].apply(lambda i: True if re.search('^\s*$', str(i)) else False)]=None ``` It could be optimized a bit by only iterating through fields that could contain empty strings: ``` if df[i].dtype == np.dtype('object') ``` But that's not much of an improvement And finally, this code sets the target strings to None, which works with Pandas' functions like `fillna()`, but it would be nice for completeness if I could actually insert a `NaN` directly instead of `None`.