How to say... match when field is a number... in mongodb?
mongodb, python
Solution
Use the `$type` operator in your `$match`:
db.zips.aggregate([
{$project : {city:{$substr:["$city",0,1]}}},
{$sort : {city : 1}},
{$match: {city: {$type: 16}}} // city is a 32-bit integer
]);
There isn't a single type value for number so you need to know which type of number you have:
32-bit integer 16
64-bit integer 18
Double 1
Or use an `$or` operator to match all types of numbers:
db.zips.aggregate([
{$project : {city:{$substr:["$city",0,1]}}},
{$sort : {city : 1}},
{$match: {$or: [{city: {$type: 1}}, {city: {$type: 16}}, {city: {$type: 18}}]}}
]);
Or even use `$not` to match all docs where `city` is not a string:
db.zips.aggregate([
{$project : {city:{$substr:["$city",0,1]}}},
{$sort : {city : 1}},
{$match: {city: {$not: {$type: 2}}}} // city is not a string
]);
UPDATED
To match all docs where `city` is a numeric string you can use a regular expression:
db.zips.aggregate([
{$project : {city:{$substr:["$city",0,1]}}},
{$sort : {city : 1}},
{$match: {city: /^\d.*$/}} // city is all digits
]);
Problem
So I have a field called 'city' in my results...the results are corrupted, some times it's an actual name, sometimes it's a number. The following code displays all the records... ``` db.zips.aggregate([{$project : {city:{$substr:["$city",0,1]}}},{$sort : {city : 1}} ]) ``` I need to modify this line to display only the records with a city who has a name that is a number (2,3,4, etc)....I think I can use '$match', but how? ``` db.zips.aggregate([{$project : {city:{$substr:["$city",0,1]}}},{$sort : {city : 1}}, {$match:{???what_to_say_here???} ]) ``` How to say 'match when city is a number'? the out put I get looks like this... ``` { "city" : "A", "_id" : "04465" }, { "city" : "1", "_id" : "02821" }, { "city" : "0", "_id" : "04689" } ``` I'm trying to display only the records with a numeric string...this is related to a larger "homework" problem but I can't even get to the actual homework question until I get past this point.