how to sleep in c

c, sleep

Solution

The `printf()` is buffering the data, you can force it to flush that data with `fflush(stdout)`:

for (i = 1; i<=10; i++) 
{  
    sleep(1); 
    printf("."); 
    fflush(stdout);
}

Problem

Possible Duplicate: Why does printf not flush after the call unless a newline is in the format string? When I run something like ``` for (i = 1; i <= 10; i++) { sleep(1); printf("."); } ``` then what I would expect is one dot per second ten times. What I get is ten dots once after ten seconds. Why is that so, and how do I get the program to actually print one point (or do other things) each second (or different time interval)?

Original source

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