Swap values in a tuple/list inside a list in python?
list, python, swap, tuples
Solution
You could use map:
map (lambda t: (t[1], t[0]), mylist)
Or list comprehension:
[(t[1], t[0]) for t in mylist]
List comprehensions are preferred and supposedly much faster than map when lambda is needed, however note that list comprehension has a strict evaluation, that is it will be evaluated as soon as it gets bound to variable, if you're worried about memory consumption use a generator instead:
g = ((t[1], t[0]) for t in mylist)
#call when you need a value
g.next()
There are some more details here: Python List Comprehension Vs. Map
Problem
I have a list of tuples like this: ``` [('foo','bar'),('foo1','bar1'),('foofoo','barbar')] ``` What is the fastest way in python (running on a very low cpu/ram machine) to swap values like this... ``` [('bar','foo'),('bar1','foo1'),('barbar','foofoo')] ``` I am currently using: ``` for x in mylist: self.my_new_list.append(((x[1]),(x[0]))) ``` Is there a better or faster way???