Troubles with boost::spirit::lex & whitespace
boost, boost-spirit, boost-spirit-lex, c++
Solution
You have created a second lexer state, but never invoked it.
Simplify and profit:
For most cases, the easiest way to have the desired effect would be to use single-state lexing with a `pass_ignore` flag on the skippable tokens:
this->self += identifier
| white_space [ lex::_pass = lex::pass_flags::pass_ignore ];
Note that this requires an `actor_lexer` to allow for the semantic action:
typedef lex::lexertl::actor_lexer<token_type> lexer_type;
Full sample:
#include <boost/spirit/include/lex_lexertl.hpp>
#include <boost/spirit/include/lex_lexertl.hpp>
namespace lex = boost::spirit::lex;
template <typename Lexer>
struct lexer_identifier : lex::lexer<Lexer>
{
lexer_identifier()
: identifier("[a-zA-Z_][a-zA-Z0-9_]*")
, white_space("[ \\t\\n]+")
{
using boost::spirit::lex::_start;
using boost::spirit::lex::_end;
this->self += identifier
| white_space [ lex::_pass = lex::pass_flags::pass_ignore ];
}
lex::token_def<> identifier;
lex::token_def<> white_space;
std::string identifier_name;
};
int main(int argc, const char *argv[])
{
typedef lex::lexertl::token<char const*,lex::omit, boost::mpl::false_> token_type;
typedef lex::lexertl::actor_lexer<token_type> lexer_type;
typedef lexer_identifier<lexer_type>::iterator_type iterator_type;
lexer_identifier<lexer_type> my_lexer;
std::string test("adedvied das934adf dfklj_03245");
char const* first = test.c_str();
char const* last = &first[test.size()];
lexer_type::iterator_type iter = my_lexer.begin(first, last);
lexer_type::iterator_type end = my_lexer.end();
while (iter != end && token_is_valid(*iter))
{
++iter;
}
bool r = (iter == end);
std::cout << std::boolalpha << r << "\n";
}
Prints
true
"WS" as a Skipper state
It is also possible you came across a sample that uses the second parser state for the skipper (`lex::tokenize_and_phrase_parse`). Let me take a minute or 10 to create a working sample for that.
Update Took me a bit more than 10 minutes (waaaah) :) Here's a comparative test, showing how the lexer states interact, and how to use Spirit Skipper parsing to invoke the second parser state:
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/lex_lexertl.hpp>
namespace lex = boost::spirit::lex;
namespace qi = boost::spirit::qi;
template <typename Lexer>
struct lexer_identifier : lex::lexer<Lexer>
{
lexer_identifier()
: identifier("[a-zA-Z_][a-zA-Z0-9_]*")
, white_space("[ \\t\\n]+")
{
this->self = identifier;
this->self("WS") = white_space;
}
lex::token_def<> identifier;
lex::token_def<lex::omit> white_space;
};
int main()
{
typedef lex::lexertl::token<char const*, lex::omit, boost::mpl::true_> token_type;
typedef lex::lexertl::lexer<token_type> lexer_type;
typedef lexer_identifier<lexer_type>::iterator_type iterator_type;
lexer_identifier<lexer_type> my_lexer;
std::string test("adedvied das934adf dfklj_03245");
{
char const* first = test.c_str();
char const* last = &first[test.size()];
// cannot lex in just default WS state:
bool ok = lex::tokenize(first, last, my_lexer, "WS");
std::cout << "Starting state WS:\t" << std::boolalpha << ok << "\n";
}
{
char const* first = test.c_str();
char const* last = &first[test.size()];
// cannot lex in just default state either:
bool ok = lex::tokenize(first, last, my_lexer, "INITIAL");
std::cout << "Starting state INITIAL:\t" << std::boolalpha << ok << "\n";
}
{
char const* first = test.c_str();
char const* last = &first[test.size()];
bool ok = lex::tokenize_and_phrase_parse(first, last, my_lexer, *my_lexer.self, qi::in_state("WS")[my_lexer.self]);
ok = ok && (first == last); // verify full input consumed
std::cout << std::boolalpha << ok << "\n";
}
}
The output is
Starting state WS: false
Starting state INITIAL: false
true
Problem
I try learning to use boost::spirit. To do that, I wanted to create some simple lexer, combine them and then start parsing using spirit. I tried modifying the example, but it doesn't run as expected (the result r isn't true). Here's the lexer: ``` #include <boost/spirit/include/lex_lexertl.hpp> namespace lex = boost::spirit::lex; template <typename Lexer> struct lexer_identifier : lex::lexer<Lexer> { lexer_identifier() : identifier("[a-zA-Z_][a-zA-Z0-9_]*") , white_space("[ \\t\\n]+") { using boost::spirit::lex::_start; using boost::spirit::lex::_end; this->self = identifier; this->self("WS") = white_space; } lex::token_def<> identifier; lex::token_def<> white_space; std::string identifier_name; }; ``` And this is the example I'm trying to run: ``` #include "stdafx.h" #include <boost/spirit/include/lex_lexertl.hpp> #include "my_Lexer.h" namespace lex = boost::spirit::lex; int _tmain(int argc, _TCHAR* argv[]) { typedef lex::lexertl::token<char const*,lex::omit, boost::mpl::false_> token_type; typedef lex::lexertl::lexer<token_type> lexer_type; typedef lexer_identifier<lexer_type>::iterator_type iterator_type; lexer_identifier<lexer_type> my_lexer; std::string test("adedvied das934adf dfklj_03245"); char const* first = test.c_str(); char const* last = &first[test.size()]; lexer_type::iterator_type iter = my_lexer.begin(first, last); lexer_type::iterator_type end = my_lexer.end(); while (iter != end && token_is_valid(*iter)) { ++iter; } bool r = (iter == end); return 0; } ``` r is true as long as there is only one token inside the string. Why is this the case? Regards Tobias