Maven project.build.directory

maven

Solution

You can find those maven properties in the super pom.

You find the jar here:

${M2_HOME}/lib/maven-model-builder-3.0.3.jar

Open the jar with 7-zip or some other archiver (or use the jar tool).

Navigate to

org/apache/maven/model

There you'll find the `pom-4.0.0.xml`.

It contains all those "short cuts":

<project>
    ...
    <build>
        <directory>${project.basedir}/target</directory>
        <outputDirectory>${project.build.directory}/classes</outputDirectory>
        <finalName>${project.artifactId}-${project.version}</finalName>
        <testOutputDirectory>${project.build.directory}/test-classes</testOutputDirectory>
        <sourceDirectory>${project.basedir}/src/main/java</sourceDirectory>
        <scriptSourceDirectory>src/main/scripts</scriptSourceDirectory>
        <testSourceDirectory>${project.basedir}/src/test/java</testSourceDirectory>
        <resources>
            <resource>
                <directory>${project.basedir}/src/main/resources</directory>
            </resource>
        </resources>
        <testResources>
            <testResource>
                <directory>${project.basedir}/src/test/resources</directory>
            </testResource>
        </testResources>
        ...
    </build>
    ...
</project>

Update

After some lobbying I am adding a link to the `pom-4.0.0.xml`. This allows you to see the properties without opening up the local jar file.

Problem

In Maven, what does the `project.build.directory` refer to? I am a bit confused, does it reference the source code directory or the target directory in the Maven project?

Original source