Compare strings based on alphabetical ordering
python
Solution
this should work:
if len(x)==len(y):
return min(x,y)
Problem
Write a function that takes two strings as arguments and returns the one which is longer. If the strings have equal length, return the one that comes first alphabetically. This is what i have so far: ``` def strings(x,y): if len(x) > len(y): return x if len(x)==len(y): return else: return y ``` I am wondering how i would write the code so it would choose the string that comes first alphabetically for the second if statement.