Array changed in a void function, is still changed outside! why? (scope)

This is a simple implementation of a sort algorithm. My question is. The array `numbers`, is declared and initialized in main. Then, I pass it like an argument in the function `sort` (Is a copy ?). Inside the `sort` function, `numbers`, now called `array` (a copy, as far as I know), is changed (sorted). So, why, after calling the function, the array `numbers` is changed (this is what I want, buy want to know why??. `array` scope is in `sort`, not `main`. ``` int main(void) { int numbers[SIZE] = { 4, 15, 16, 50, 8, 23, 42, 108 }; for (int i = 0; i < SIZE; i++) printf("%d ", numbers[i]); printf("\n"); sort(numbers, SIZE); for (int i = 0; i < SIZE; i++) printf("%d ", numbers[i]); printf("\n"); return 0; } void sort(int array[], int size) { int swaps = 0; while(swaps==0) { for(int i = 0; i < size ; i++) { for(int j = i + 1; j < size ; j++) { if( array[i] > array[j] ) { // Swapping int temp = array[i]; array[i] = array[j]; array[j] = temp; swaps ++; } } } } } ```