How is the Java compiler able to distinguish between those two constructors/methods?
ambiguous, java, variadic-functions
Solution
It's always the most specific method that is called.
new MyClass("foobar");
searches to call that constructor which takes an object of type `String` as it's only argument.
and, `var-args` method will be used iff matching `non-var-args` method doesn't exist.
Problem
``` public class MyClass { private String string; private Object[] objects; // constructor 1 public MyClass(String string, Object... objects) { this.string = string; this.objects = objects; } // constructor 2 public MyClass(String string) { this.string = string; } public static void main(String[] args) { MyClass myClass = new MyClass("foobar"); } } ``` In that case, how did the Java compiler decide to use `constructor 2` instead of `constructor 1`? Why no `The constructor ... is ambiguous` or a similar error occurs? PS: the question works with classic methods too.