Assigning a value to a variable in a chain in Java

Possible Duplicate: Java - Order of Operations - Using Two Assignment Operators in a Single Line If we assign a variable a value in a chain like the following, ``` int x=10, y=15; int z=x=y; System.out.println(x+" : "+y+" : "+z); ``` then the value of all three variables `x`, `y` and `z` becomes `15`. I however don't understand the following phenomenon with an array. ``` int array[]={10, 20, 30, 40, 50}; int i = 4; array[i] = i = 0; System.out.println(array[0]+" : "+array[1]+" : "+array[2]+" : "+array[3]+" : "+array[4]); ``` It outputs `10 : 20 : 30 : 40 : 0`. It replaces the value of the last element which is `array[4]` with `0`. Regarding previous assignment statement - `int z=x=y;`, I expect the value of the first element means `array[0]` to be replaced with `0`. Why is it not the case? It's simple but I can't figure it out. Could you please explain? By the way, this assignment statement `array[i] = i = 0;` is dummy and it has no value of its own in this code and should no longer be used but I just wanted to know how thing actually works in this case.