"Error: expression must have a pointer type" when using the "this" keyword
c++, this
Solution
You have to use
this->grid[i*col + j].key1
this->grid[i*col + j].key2
That is because even if it is true that your grid is a pointer, you have allocated in the are pointed by its memory an array of `Square` object. So when you use the [] operator you are obtaining an object of type `Square` and not a `Square*` and for a `Square` object you hve to use the . operator and not the -> operator.
Problem
So I made a parent class, which i will call `Parent` that has a `Square*` grid member variable. The grid variable is a pointer to a large array of Squares, which contain `key` member variables. (Think of this project as a hashtable) The problem is I am making a function in the `Parent` class that edits the key variables in the `Square` array, and getting an error. This line of code compiles: ``` this->grid = new Square[row*col]; ``` but this line does not compile: ``` this->grid[i*col + j]->key1 = j; ``` it underlines `this` and says expression must have a pointer type. I was wondering if anyone had ideas to what i may be doing wrong? ``` void Parent::initialize(int row,int col) { this->grid = new Square[row*col]; for(int i = 0; i < row; i++) { for(int j = 0;j < col; j++) { this->grid[i*col + j]->key1 = j; this->grid[i*col + j]->key2 = i; } } ```