How to make gcc link strong symbol in static library to overwrite weak symbol?

c, gcc, ld, weak-linking

Solution

Generally speaking: if you don't put a weak implementation into your `main`, the linker will resolve it at last at runtime. But if you implement it in `main.c`, you will only be able to override it with a strong bound (`bar.c`) when linking this static.

Please read https://bottomupcs.com/ch09s05.html - it contains a lot of interesting stuff on this topic.

I've made a test myself:

bar.c

#include <stdio.h>

void bar()
{
        puts("bar.c: i'm the strong bar()");
}

baz.c

#include <stdio.h>

void __attribute__((weak)) bar() 
{
        puts("baz.c: i'm the weak bar()");
}

main.c

#include <stdio.h>

#ifdef V2
        void __attribute__((weak)) bar()
        {
                puts("main: i'm the build in weak bar()");
        }
#else
        void __attribute__((weak)) bar();
#endif

int main()
{
    bar();
    return 0;
}

My Makefile:

all:
    gcc -c -o bar.o bar.c
    gcc -shared -fPIC -o libbar.so bar.o
    gcc -c -o baz.o baz.c
    gcc -shared -fPIC -o libbaz.so baz.o
    gcc -o main1 main.c -L. -lbar -lbaz
    gcc -o main2 main.c -L. -lbaz -lbar
    LD_LIBRARY_PATH=. ./main1                                   # => bar.c
    LD_LIBRARY_PATH=. ./main2                                   # => baz.c
    LD_LIBRARY_PATH=. LD_PRELOAD=libbaz.so ./main1              # => baz.c (!!)
    LD_LIBRARY_PATH=. LD_PRELOAD=libbaz.so ./main2              # => baz.c
    gcc -o main3 main.c bar.o baz.o
    gcc -o main4 main.c baz.o bar.o
    ./main3                                                     # => bar.c
    ./main4                                                     # => bar.c
    gcc -DV2 -o main5 main.c -L. -lbar -lbaz
    gcc -DV2 -o main6 main.c -L. -lbaz -lbar
    LD_LIBRARY_PATH=. ./main5                                   # => main's implementation
    LD_LIBRARY_PATH=. ./main6                                   # => main's implementation
    gcc -DV2 -o main7 main.c -L. -lbar -lbaz
    gcc -DV2 -o main8 main.c -L. -lbaz -lbar
    LD_LIBRARY_PATH=. LD_PRELOAD=libbaz.so ./main7              # => main's implementation
    LD_LIBRARY_PATH=. LD_PRELOAD=libbaz.so ./main8              # => main's implementation
    gcc -DV2 -o main9  main.c -L. -lbar -lbaz
    gcc -DV2 -o main10 main.c -L. -lbaz -lbar
    LD_LIBRARY_PATH=. LD_PRELOAD=libbar.so ./main9              # => main's implementation
    LD_LIBRARY_PATH=. LD_PRELOAD=libbar.so ./main10             # => main's implementation
    gcc -c bar.c
    gcc -c baz.c
    gcc -o main11 main.c bar.o baz.o
    gcc -o main12 main.c baz.o bar.o
    ./main11                                                    # => bar.c
    ./main12                                                    # => bar.c
    gcc -o main13 -DV2 main.c bar.o baz.o
    gcc -o main14 -DV2 main.c baz.o bar.o
    ./main13                                                    # => bar.c
    ./main14                                                    # => bar.c

Take a look at main1 && main2... if you don't put any weak implementation into `main.c` but keep the weak one in a library and the strong one in another lib., you'll be able to override the weak one if the strong lib defines a strong implementation of `bar()`.

Problem

My problem can be summarised in the following: bar.c: ``` #include <stdio.h> void bar() { printf("bar\n"); } ``` main.c: ``` #include <stdio.h> void __attribute__((weak)) bar() { printf("foo\n"); } int main() { bar(); return 0; } ``` Makefile: ``` all: gcc -c bar.c ar -rc libbar.a bar.o gcc main.c -L. -lbar ``` Output: ``` $ ./a.out foo ``` So the weak symbol bar in main.c is not overwritten by the strong symbol in bar.c due to bar.c being linked to main.c in a static library libbar.a. How can I tell gcc to make the strong symbol in libbar.a to overwritten the weak symbol in main.c?

Original source

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