Difference between these two conditions?

if-statement, java, string

Solution

There are no difference between them at all. Many programmers use the 2nd way just to make sure that they don't get a `NullPointerException`. That's all.

    String str = null;

    if(str.equals("test")) {  // NullPointerException
        System.out.println("After");
    }
    if("test".equals(str)) {  // No Exception will be thrown. Will return false
        System.out.println("Before");
    }

Problem

Sorry if my question is silly or not it doesnot matter. But i just want to know what will happen in these two conditions. ``` public class Test { public static void main(String[] args) { String str="test"; if(str.equals("test")){ System.out.println("After"); } if("test".equals(str)){ System.out.println("Before"); } } } ``` Both are giving same results only. But i know there is some reasons.I dont know about that. What is difference between these two conditions?

Original source