call the same jQuery function in multiple buttons

html, javascript, jquery

Solution

First solution :

function doClick(e) { 
   $('#modal').reveal({ 
     animation: 'fade',
     animationspeed: 150,
     closeonbackgroundclick: true, 
     dismissmodalclass: 'close'
   });
   return false;
}
$('#button1').click(doClick);
$('#button2').click(doClick);

Second solution :

Give a class "someClass" to all the involved buttons

<input type=button class=someClass ...

and do

$('.someClass').click(function(e) { 
...
});

Third solution :

Use the comma to separate ids :

$('#button1, #button2').click(function(e) { 
...
});

Generally, the best solution is the second one : it allows you to add buttons in your code without modifying the javascript part. If you add some of those buttons dynamically, you may even do

$(document).on('click', '.someClass', function(e) { 
...
});

Problem

I am not really familiar with jQuery. I have this code that I downloaded to create a fade in/fade out popup form. Here's the code: ``` <script type='text/javascript'> $(document).ready(function() { $('#button').click(function(e) { $('#modal').reveal({ animation: 'fade', animationspeed: 150, closeonbackgroundclick: true, dismissmodalclass: 'close' }); return false; }); }); </script> ``` The code above executes when a button with an `id='button'` is clicked. Now I have multiple buttons, how can I call this function in all buttons? I tried setting the `id` of all buttons to `button` but only the first button works. Any help would be very much appreciated. By the way I forgot to mention, in my .php file i have this codes: ``` for ($c=1;$c<=5;$c++){ echo "<input type='button' id='button'"> }; ``` This php code will display 5 buttons with the same id which is 'button'. What I want to happen is when I click any of the 5 buttons the jQuery function will execute which is popping up a fade in/fade out form.

Original source