Java sorting an String Array by a Substring of characters

arrays, java, sorting

Solution

You can use a `Comparator`, and use `Array#sort` method with it, to sort it according to your need: -

String[] yourArray = new String[3];
yourArray[0] = "gtrd3455";
yourArray[1] = "ltzy96545";
yourArray[2] = "lopa475";

Arrays.sort(yourArray, new Comparator<String>() {
    public int compare(String str1, String str2) {
        String substr1 = str1.substring(4);
        String substr2 = str2.substring(4);

        return Integer.valueOf(substr2).compareTo(Integer.valueOf(substr1));
    }
});

System.out.println(Arrays.toString(yourArray));

OUTPUT: -

[ltzy96545, gtrd3455, lopa475]

Problem

I need to sort an array of strings like the following, by a substring of characters: ``` [0] = "gtrd3455"; [1] = "wsft885"; [2] = "ltzy96545"; [3] = "scry5558"; [4] = "lopa475"; ``` I need to sort by the following "3455, 885, 96545, 5558, 475" I need to substring off the first 4 characters of the array, sort it and display back in an array like the output below. The output should be an array like: ``` [0] = "ltzy96545"; [1] = "scry5558"; [2] = "gtrd3455"; [3] = "wsft885"; [4] = "lopa475"; ``` Example of how I can do this in Java?

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