How do you pass a member function pointer?
c++, class, function, member, pointers
Solution
To call a member function by pointer, you need two things: A pointer to the object and a pointer to the function. You need both in `MenuButton::SetButton()`
template <class object>
void MenuButton::SetButton(int xPos, int yPos, LPCWSTR normalFilePath,
LPCWSTR hoverFilePath, LPCWSTR pressedFilePath,
int Width, int Height, object *ButtonObj, void (object::*ButtonFunc)())
{
BUTTON::SetButton(xPos, yPos, normalFilePath, hoverFilePath, pressedFilePath, Width, Height);
this->ButtonObj = ButtonObj;
this->ButtonFunc = ButtonFunc;
}
Then you can invoke the function using both pointers:
((ButtonObj)->*(ButtonFunc))();
Don't forget to pass the pointer to your object to `MenuButton::SetButton()`:
testMenu::testMenu()
:MenuScreen("testMenu")
{
x.SetButton(100,100,TEXT("buttonNormal.png"), TEXT("buttonHover.png"),
TEXT("buttonPressed.png"), 100, 40, this, test2);
draw = false;
}
Problem
I am trying to pass a member function within a class to a function that takes a member function class pointer. The problem I am having is that I am not sure how to properly do this within the class using the this pointer. Does anyone have suggestions? Here is a copy of the class that is passing the member function: ``` class testMenu : public MenuScreen{ public: bool draw; MenuButton<testMenu> x; testMenu():MenuScreen("testMenu"){ x.SetButton(100,100,TEXT("buttonNormal.png"),TEXT("buttonHover.png"),TEXT("buttonPressed.png"),100,40,&this->test2); draw = false; } void test2(){ draw = true; } }; ``` The function x.SetButton(...) is contained in another class, where "object" is a template. ``` void SetButton(int xPos, int yPos, LPCWSTR normalFilePath, LPCWSTR hoverFilePath, LPCWSTR pressedFilePath, int Width, int Height, void (object::*ButtonFunc)()) { BUTTON::SetButton(xPos, yPos, normalFilePath, hoverFilePath, pressedFilePath, Width, Height); this->ButtonFunc = &ButtonFunc; } ``` If anyone has any advice on how I can properly send this function so that I can use it later.