Command line .cmd/.bat script, how to get directory of running script
batch-file
Solution
Raymond Chen has a few ideas:
https://devblogs.microsoft.com/oldnewthing/20050128-00/?p=36573
Quoted here in full because MSDN archives tend to be somewhat unreliable:
The easy way is to use the `%CD%` pseudo-variable. It expands to the current working directory.
`set OLDDIR=%CD%` `.. do stuff ..` `chdir /d %OLDDIR% &rem restore current directory`
(Of course, directory save/restore could more easily have been done with `pushd`/`popd`, but that's not the point here.)
The `%CD%` trick is handy even from the command line. For example, I often find myself in a directory where there's a file that I want to operate on but... oh, I need to chdir to some other directory in order to perform that operation.
`set _=%CD%\curfile.txt` `cd ... some other directory ...` `somecommand args %_% args`
(I like to use `%_%` as my scratch environment variable.)
Type `SET /?` to see the other pseudo-variables provided by the command processor.
Also the comments in the article are well worth scanning for example this one (via the WayBack Machine, since comments are gone from older articles):
http://blogs.msdn.com/oldnewthing/archive/2005/01/28/362565.aspx#362741
This covers the use of %~dp0:
If you want to know where the batch file lives: `%~dp0`
`%0` is the name of the batch file. `~dp` gives you the drive and path of the specified argument.
Problem
How can you get the directory of the script that was run and use it within the .cmd file?