Echo of String with Double Quotes to Output file using Windows Batch

batch-file, windows

Solution

Try replacing all `"` in `Text` with `^"`.

`^` is escape character so the the `"` will be treated as regular character

you can try the following:

:AddText %1 %2
set _Text=%~1%
set Text=%_Text:"=^^^"%

... rest of your code

REM for example if %1 is "blah"blah"blah"
REM _Text will be blah"blah"blah
REM Text will be blah^"blah^"blah

Other characters that could cause you errors (you can solve it with the above solution) are:

\ & | > < ^

Problem

I'm attempting to rewrite a configuration file using a Windows Batch file. I'm looping through the lines of the file and looking for the line that I want to replace with a specified new line. I have a 'function' that writes the line to the file ``` :AddText %1 %2 set Text=%~1% set NewLine=%~2% echo "%Text%" | findstr /C:"%markerstr%" 1>nul if errorlevel 1 ( if not "%Text%" == "" ( setlocal EnableDelayedExpansion ( echo !Text! ) >> outfile.txt ) else ( echo. >> outfile.txt ) ) else ( set NewLine=%NewLine"=% setlocal EnableDelayedExpansion ( echo !NewLine! ) >> outfile.txt ) exit /b ``` The problem is when %Text% is a string with embedded double quotes. Then it fails. Possibly there are other characters that would cause it to fail too. How can I get this to be able to work with all text found in the configuration file?

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