BASH: print the next monday of date

bash

Solution

If GNU `date` (or any other `date`) accepts some variation of "monday after $DAYCHECK", I haven't seen it. I think you have to do the math.

$ day_of_week=$( date +%u --date $DAYCHECK)   # 1 = Monday, ... 7 = Sunday
$ date --date "$DAYCHECK +$((8-day_of_week)) days"

If `DAYCHECK` is already a Monday, you'll get the following Monday. If you want `DAYCHECK` instead, you'll need to handle it separately:

$ if (( day_of_week == 1 )); then
> date --date "$DAYCHECK"
> else
> date --date "$DAYCHECK +$((8-day_of_week)) days"
> fi

Problem

How can I calculate the date of the Monday of next week? For example, if I have one variable with this day: ``` DAYCHECK=2012-10-24 ``` the calculation of the next-monday doesn't work: ``` date -d $DAYCHECK -dnext-monday +%Y%m%d ``` UPDATE: I have solved whit this method: ``` numdaycheck=`date -d $DAYCHECK +%u` sum=$((8-$numdaycheck)) date=`date -d "$DAYCHECK $sum days" +%Y%m%d` ```

Original source