Variable length argument list of set type

Question

Alright, I'm pretty sure that this has been discussed before in some way or another, but I'm apparently too stupid to find it. First: I'm NOT looking for va_list and the other macros. What I am looking for is something like the main-function parameters. The default prototype, as all of you know is: ``` int main(int argc, char *argv[]); ``` Now, I want something similar for my program, but don't know how exactly. Let's assume we have this function: ``` void Function(int argc, unsigned short *args[]) { for(int i = 0; i < argc; ++i) printf("%hu ", args[i]); } ``` And I want something like this function call: ``` Function(5, 1, 2, 3, 4, 5); ``` Would that work? Because I don't want the 'cluttering' of va_list, nor do I want to create: ``` void AnotherFunction() { unsigned short Args[] = { 1, 2, 3, 4, 5 }; Function(5, Args); } ``` Simply because in that case I would only need a simple pointer. Could someone please point me in the right direction? Thank you very much. Edit: Thank you everyo…

Accepted Answer

A g++ specific solution:

```
const size_t MAX_ARGS = 42;

void Function(int argc, const unsigned short (&args)[MAX_ARGS])
{
}

int main()
{
    Function(5, {1,2,3,4,5});
}
```

If you don't actually need the `argc` parameter, you can write a template:

```
template<size_t N>
void Function(const unsigned short(&args)[N])
{
    // use N
}
```

This works in C++03. The array needs to be const, or else you can't pass a temporary initializer list like that. If you need to modify the elements inside the function, you'll need to make a copy.

Variable length argument list of set type

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