How can I check if a string represents an int, without using try/except?
integer, python, string
Solution
If you're really just annoyed at using `try/except`s all over the place, please just write a helper function:
def represents_int(s):
try:
int(s)
except ValueError:
return False
else:
return True
>>> print(represents_int("+123"))
True
>>> print(represents_int("10.0"))
False
It's going to be WAY more code to exactly cover all the strings that Python considers integers. I say just be pythonic on this one.
Problem
Is there any way to tell whether a string represents an integer (e.g., `'3'`, `'-17'` but not `'3.14'` or `'asfasfas'`) Without using a try/except mechanism? ``` is_int('3.14') == False is_int('-7') == True ```