Create a Python list filled with the same string over and over and a number that increases based on a variable.

Question

I'm trying to create a list that is populated by a reoccurring string and a number that marks which one in a row it is. The number that marks how many strings there will be is gotten from an int variable. So something like this: ``` b = 5 a = range(2, b + 1) c = [] c.append('Adi_' + str(a)) ``` I was hoping this would create a list like this: ``` c = ['Adi_2', 'Adi_3', 'Adi_4', 'Adi_5'] ``` Instead I get a list like this ``` c = ['Adi_[2, 3, 4, 5]'] ``` So when I try to print it in new rows ``` for x in c: print"Welcome {0}".format(x) ``` The result of this is: ``` Welcome Adi_[2, 3, 4, 5] ``` The result I want is: ``` Welcome Adi_2 Welcome Adi_3 Welcome Adi_4 Welcome Adi_5 ``` If anybody has Ideas I would appreciate it.

Accepted Answer

You almost got it:

```
for i in a:
    c.append('Adi_' + str(i))
```

Your initial line was transforming the whole list `a` as a string.

Note that you could get rid of the loop with a list comprehension and some string formatting:

```
c = ['Adi_%s' % s for s in a] 
```

or

```
c = ['Adi_{0}'.format(s) for s in a] #Python >= 2.6
```

Create a Python list filled with the same string over and over and a number that increases based on a variable.

Solution

Problem