java - arraylist check if element exits here ignore the case

java

Solution

You could put all your strings in a `TreeSet` with a custom Comparator that ignores the case:

List<String> list = Arrays.asList("Chicken", "Duck");
Set<String> set=  new TreeSet<String>(String.CASE_INSENSITIVE_ORDER);
set.addAll(list);
System.out.println(set.contains("Chicken")); //true
System.out.println(set.contains("chicken")); //true

For more complex strategies / locale, you can also use a Collator:

final Collator ignoreCase = Collator.getInstance();
ignoreCase.setStrength(Collator.SECONDARY);

List<String> list = Arrays.asList("Chicken", "Duck");
Set<String> set=  new TreeSet<String>(new Comparator<String>() {
    @Override
    public int compare(String o1, String o2) {
        return ignoreCase.compare(o1, o2);
    }
});
set.addAll(list);
System.out.println(set.contains("Chicken"));
System.out.println(set.contains("chicken"));

Problem

Hi i have the arraylist it stores the string values. I want to check the some string is exists in the list or not. Here i want ignore the case sensitive. code ``` public static ArrayList< String > arrFoodItems = new ArrayList< String >(); if(arrFoodItems.contains("string")) { System.out.println("already available in the List."); } else { System.out.println("Not available"); } ``` It's working fine. But in the following example it fails. How to do it without using loops. Example: List contains: "Rice, Chicken,..." Now you are check for "rice" is exits in the list. In this case we are getting "not exists". Don't using this ``` for(int i=0; i < arrFoodItems.size(); i++) { if(arrFoodItems.get(i)..equalsIgnoreCase(string)) { System.out.println("already available in the List."); } } ```

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