How to work with infinity arguments in a function (like PHP's isset())

function, param, parameter-passing, parameters, php

Solution

`func_get_args` will do what you want:

function infinite_parameters() {
    foreach (func_get_args() as $param) {
        echo "Param is $param" . PHP_EOL;
    }
}

You can also use `func_get_arg` to get a specific parameter (it's zero-indexed):

function infinite_parameters() {
    echo func_get_arg(2);
}

But be careful to check that you have that parameter:

function infinite_parameters() {
    if (func_num_args() < 3) {
        throw new BadFunctionCallException("Not enough parameters!");
    }
}

You can even mix together `func_*_arg` and regular parameters:

function foo($param1, $param2) {
    echo $param1; // Works as normal
    echo func_get_arg(0); // Gets $param1
    if (func_num_args() >= 3) {
        echo func_get_arg(2);
    }
}

But before using it, think about whether you really want to have indefinite parameters. Would an array not suffice?

Problem

You know how PHP's `isset()` can accept multiple (no limit either) arguments? Like I can do: ``` isset($var1,$var2,$var3,$var4,$var5,$var6,$var7,$var8,$var9,$var10,$var11); //etc etc ``` How would I be able to do that in my own function? How would I be able to work with infinity arguments passed? How do they do it?

Original source

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