Using in range(..) in an if-else statment

python

Solution

It is because the input data is string. So it flows to else. Convert it into integer then all will be fine.

>>> number = raw_input("> ")
>>> type(number)
<type 'str'>
int(number) converts to <type 'int'>

Please use:

if int(number) in range(1, 6):
    print "You entered a number in the range of 1 to 5"
elif int(number) in range(6, 11):
    print "You entered a number in the range of 6 to 10"
else:
    print "Your number wasn't in the correct range"

Problem

python 2.7 Is it possible to do this: ``` print "Enter a number between 1 and 10:" number = raw_input("> ") if number in range(1, 5): print "You entered a number in the range of 1 to 5" elif number in range(6, 10): print "You entered a number in the range of 6 to 10" else: print "Your number wasn't in the correct range" ``` I find if I put a number between 1 to 10 it always falls to the else statement. Is this an incorrect use of in range in an if-else statement? Many thanks in advance,

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