nth character of string to int

c++

Solution

How about:

for (int i = 0; i < str.size(); i++)
    if (isdigit(str[i]))
        ints[i] = str[i] - '0';

Or maybe:

for (string::const_iterator it = str.begin();
     it != str.end(); it++)
         if (isdigit(*it))
             ints[i] = *it - '0';

Problem

How can I convert nth character of string to number? I have a long number expressed as string and I'd like to make an array of it, where each character would be seperate number. I've tried with followed piece of code: ``` #include <iostream> #include <string> #include <sstream> using namespace std; int main() { string str ="73167176531330624919225119674426574742355349194934969835203127745063262395783180169848018"; int ints[1000] = {0}; for (int i = 0; i < str.size(); i++) { istringstream ss(str[i]); ss >> ints[i]; } cout << ints[9] << endl; return 0; } ``` But it doesn't work.

Original source