How do I print uint32_t and uint16_t variables' value?
c, gcc
Solution
You need to include `inttypes.h` if you want all those nifty new format specifiers for the `intN_t` types and their brethren, and that is the correct (ie, portable) way to do it, provided your compiler complies with C99. You shouldn't use the standard ones like `%d` or `%u` in case the sizes are different to what you think.
It includes `stdint.h` and extends it with quite a few other things, such as the macros that can be used for the `printf/scanf` family of calls. This is covered in section 7.8 of the ISO C99 standard.
For example, the following program:
#include <stdio.h>
#include <inttypes.h>
int main (void) {
uint32_t a=1234;
uint16_t b=5678;
printf("%" PRIu32 "\n",a);
printf("%" PRIu16 "\n",b);
return 0;
}
outputs:
1234
5678
Problem
I am trying to print an `uint16_t` and `uint32_t` value, but it is not giving the desired output. ``` #include <stdio.h> #include <netinet/in.h> int main() { uint32_t a = 12, a1; uint16_t b = 1, b1; a1 = htonl(a); printf("%d---------%d", a1); b1 = htons(b); printf("\n%d-----%d", b, b1); return 0; } ``` I also used ``` printf("%"PRIu32, a); ``` which is showing an error. How do I print these values and what will be the desired output?