sizeof in c++ showing string size one less
c++, string
Solution
`sizeof(s)` gives you the size of the object `s`, not the length of the string stored in the object `s`.
You need to write this:
cout << s.size() << endl;
Note that `std::basic_string` (and by extension `std::string`) has a `size()` member function. `std::basic_string` also has a `length` member function which returns same value as `size()`. So you could write this as well:
cout << s.length() << endl;
I personally prefer the `size()` member function, because the other containers from the standard library such as `std::vector`, `std::list`, `std::map`, and so on, have `size()` member functions but not `length()`. That is, `size()` is a uniform interface for the standard library container class templates. I don't need to remember it specifically for `std::string` (or any other container class template). The member function `std::string::length()` is a deviation in that sense.
Problem
In C++ I am trying to get size of a `string` say "gibbs"; When I am using `sizeof` function it is returning me size less then one of actual size. I have below code : ``` string s = "gibbs"; cout << sizeof(s) <<endl; ``` and output is : 4. I guess it should be 5. How to fix this issue. We can add +1 always to return of sizeof but will that be perfect solution ?