Android random string generator

Question

I have a problem. I want to draw a random String something like this aXcFg3s2. What i doing bad ? How change my `random()` ``` private String random; private String charsEntered; private EditText et; private Button ok; CaptchaInterface.OnCorrectListener mCorrectListener; public void setOnCorrectListener(CaptchaInterface.OnCorrectListener listener) { mCorrectListener = listener; } public TextCaptcha(Context context) { super(context); getWindow().requestFeature(Window.FEATURE_NO_TITLE); } public static String random() { Random generator = new Random(); String x = (String) (generator.nextInt(96) + 32); return x; } public void onCreate(Bundle icicle) { setContentView(R.layout.main); random = random(); TextView display = (TextView) findViewById(R.id.textView1); display.setText("Random Number: " + random); // Show the random number et = (EditText) findViewById(R.id.etNumbers); ok = (Button) findViewById(R.id.button1); ok.setOnClickListener(this); } public void onClick(View arg0) { // TODO A…

Accepted Answer

There are a few things wrong with your code.

You cannot cast from an int to a string. Cast it to a char instead. This however will only give you a single char so instead you could generate a random number for the length of your string. Then run a for loop to generate random chars. You can define a StringBuilder as well and add the chars to that, then get your random string using the `toString()` method

example:

```
public static String random() {
    Random generator = new Random();
    StringBuilder randomStringBuilder = new StringBuilder();
    int randomLength = generator.nextInt(MAX_LENGTH);
    char tempChar;
    for (int i = 0; i < randomLength; i++){
        tempChar = (char) (generator.nextInt(96) + 32);
        randomStringBuilder.append(tempChar);
    }
    return randomStringBuilder.toString();
}
```

Also, you should use `random.compareTo()` rather than ==

Android random string generator

Solution

Problem