Passing more kwargs into a function than initially set
keyword-argument, python
Solution
To clarify Martijn Pieters's answer (for sake of clarity). It's possible if you change the function signature to:
`def mydef(a, b, **kwargs):`
This means it's not possible without changing the signature. But if that's not a problem it'll work.
Problem
Is there a way to send more kwargs into a function than is called for in the function call? Example: ``` def mydef(a, b): print a print b mydict = {'a' : 'foo', 'b' : 'bar'} mydef(**mydict) # This works and prints 'foo' and 'bar' mybigdict = {'a' : 'foo', 'b' : 'bar', 'c' : 'nooooo!'} mydef(**mybigdict) # This blows up with a unexpected argument error ``` Is there any way to pass in `mybigdict` without the error? `'c'` would never be used in `mydef` in my ideal world and would just be ignored. Thanks, my digging has not come up with what I am looking for. Edit: Fixed the code a bit. The `mydef(a, b, **kwargs)` was the form that I was looking for, but the inspect function args was a new thing to me and definitely something for my toolbox. Thanks everyone!