Static pointer and operator new
c++
Solution
That's because static locals are initialized only once when control first passes through the initialization code. So although you call the function multiple times the following line:
static X* px1 = new X(i);
will only be executed in the very first call (with `i` being zero) and the variable will persist its value between the function calls.
Yes, you can `delete` `px1` but you'd better set it to null afterwards to avoid double-free and undefined behavior. You also have leaks with objects pointed to by `px2` - you have to take care of those objects too.
Problem
``` class X { public: X(int i) : num(i){} int num; }; void f(int i){ static X* px1 = new X(i); X* px2 = new X(i); cout<<px1->num; cout<<px2->num<<' '; }; void main(){ for (int i=0;i<5;i++) f(i); } ``` This code will output `00 01 02 03 04`, but I don't quite understand why static pointer `px1` can't change its value using `operator new`. Also, this code has memory leakage problem. Can I use `delete` with `px1`? Will using `delete` on both pointers solve memory leakage problem?