why I can access private method from outside in C++?
c++
Solution
disp() is public since you're calling it through an A* and disp() is declared as public in A. Since it is virtual, B's version of disp gets called, but that doesn't affect whether it's public or private.
Problem
Possible Duplicate: Why is it allowed to call derived class' private virtual method via pointer of base class? Recently, I met a strange question, plz refer to following code: ``` #include <iostream> using namespace std; class A { public: virtual void disp() { cout<<"A disp"<<endl; } }; class B : public A { private: void disp() { cout<<"B disp"<<endl; } }; int main() { A a; a.disp(); A *b = new B(); b->disp(); } ``` and the output is: ``` A disp B disp ``` I'm wondering why pointer b can access disp()? It's private! Isn't it?