Python argument counting
command-line-arguments, python
Solution
Yes, Python uses zero-based indexing as you surmised (and as many other programming languages also do).
`sys.argv` is a list of strings.
`sys.argv[0]` will contain the name of the script, and subsequent entries in this list of strings will contain command line arguments provided to the script.
I was going to provide an example, but what you have in your post is as good as I could come up with.
Finally, as @GregHewgill points out in a helpful comment below, the Python docs provide more information on this as well.
Problem
I just got into arguments in Python and I find it strange the way the arguments system works in Python (I'm not sure about other languages). For example: ``` from sys import argv arg1, arg2, arg3 = argv print "First argument: ", arg1 print "Second argument: ", arg2 print "Third argument: ", arg3 ``` When I run this in command line with the arguments that follow: ``` python example.py First Second ``` It gives the output: ``` First argument: example.py Second argument: First Third argument: Second ``` Does this mean that python starts counting from zero? Or is there some different or some more reasons it does that. It's odd, but interesting.