TypeError: __init__() takes exactly 1 argument (3 given) pyXML

I've recently started to learn how to use python to parse xml files. I took the tutorial from http://pyxml.sourceforge.net/topics/howto/node12.html When I run the following code I get the error: ``` Traceback (most recent call last): File "C:\Users\Name\Desktop\pythonxml\tutorials\pythonxml\pyxml sourceforge\5.1 Comic Colection\SearchForComic.py", line 30, in -toplevel- dh = FindIssue('sandman', '62') TypeError: __init__() takes exactly 1 argument (3 given) ``` code: ``` from xml.sax import saxutils class FindIssue(saxutils.DefaultHandler): def __init___(self, title, number): self.search_title, self.search_number = title, number def startElement(self, name, attrs): #if it's not a comic element, ignore it if name!= 'comic': return # look for the title and number sttributes (see text) title = attrs.get('title', None) number = attrs.get('number', None) if (title == self.search_title and number == self.search_number): print title, '#' +str (number), 'found' from xml.sax import make_parser from xml.sax.handler import feature_namespaces if __name__ == '__main__': #Create a parser parser = make_parser() #tell the parser that we are not interested in XML namespaces parser.setFeature(feature_namespaces, 0) #create the handler dh = FindIssue('sandman', '62') #tell the parse to use our handler parser.setContentHandler(dh) #parse the input parser.parse('collection.xml') ``` also on the last line I'm passing the file its in the current working directory is this the correct way to address the file?