How do I fix this code to create an array of strings?
arrays, c
Solution
If you would like to create an array of strings, you are missing an asterisk, and terminating zeros:
char str1[] = {'f','i','\0'};
char str2[] = {'s','e','\0'};
char str3[] = {'t','h','\0'};
char *arry_of_string[] = {str1,str2,str3};
There is an easier way of doing the individual strings, too:
char str1[] = "fi";
char str2[] = "se";
char str3[] = "th";
char *arry_of_string[] = {str1,str2,str3};
When you use the `char x[] = "..."` construct, the content of your string literal (which includes a terminating zero) is copied into memory that you are allowed to write, producing the same effect as `char x[] = {'.', '.', ... '\0'}` construct.
Problem
I want to create an array of strings. Here is the code: ``` #include <stdio.h> int main(void){ char str1[] = {'f','i'}; char str2[] = {'s','e'}; char str3[] = {'t','h'}; char arry_of_string[] = {str1,str2,str3}; printf("%s\n",arry_of_string[1]); return 0; } ``` This is the line that doesn't work: ``` char arry_of_string[] = {str1,str2,str3}; ``` How do I correct it?