Why is part of my code not executed?

Question

I'm using Visual C++ to compile my plug-in for Cinema 4D. ``` GeDebugOut("-->"); subroot = NULL; head = NULL; tail = NULL; success = PolygonizeHierarchy(source, hh, head, tail, &subroot, malloc); if (!success) { /* .. */ } String str("not set."); if (subroot) { GeDebugOut("yes"); str = "yes!"; GeDebugOut("Subroot name: " + subroot->GetName()); } else { GeDebugOut("no"); str = "no!"; } GeDebugOut("Is there a subroot? " + str); GeDebugOut("<--"); ``` The expected output is the following: ``` --> yes Subroot name: Cube Is there a subroot? yes <-- ``` (or the same with "no" instead.) But I get ``` --> yes <-- ``` Why are two prints missing here? This is the declaration of `GeDebugOut`. ``` void GeDebugOut(const CHAR* s, ...); void GeDebugOut(const String& s); ``` The `String` class is concatenateable. It overloads the `+` operator. ``` String(void); String(const String& cs); String(const UWORD* s); String(const CHAR* cstr, STRINGENCODING type = STRINGENCODING_XBIT); String(LONG count, UWO…

Accepted Answer

You need to use `GeDebugOut` like you use `printf`:

```
GeDebugOut("Some message =  %s ", whatever);
```

where `whatever` is a c-string, i.e its type is `char*`.

Since an overload of `GeDebugOut` accepts `String` type also, then I think you need to use unicode as:

```
GeDebugOut(L"Is there a subroot?   " + str);
        // ^ note this!
```

because my suspicion is that if unicode is enabled, then `CHAR` is basically `wchar_t`, not `char`. And because of this, the string concatenation doesn't work, as the string-literal doesn't implicitly get converted into `String` type, to be passed to `+` overload.

Why is part of my code not executed?

Solution

Problem