C++11 lambda capture by value captures at declaration point
c++, c++11, lambda
Solution
Lambda functions are invoked by actually passing captured parameters to the function.
`value` is equal to 0 at the point where the lambda is defined (and `value` is captured). Since you are capturing by value, it doesn't matter what you do to `value` after the capture.
If you had captured `value` by reference, then you would see a 1 printed because even though the point of capture is still the same (the lambda definition) you would be printing the current value of the captured object and not a copy of it created when it was captured.
Problem
The code below prints 0, but I expect to see a 1. My conclusion is that lambda functions are not invoked by actually passing captured parameters to the functions, which is more intuitive. Am I right or am I missing something? ``` #include <iostream> int main(int argc, char **argv){ int value = 0; auto incr_value = [&value]() { value++; }; auto print_value = [ value]() { std::cout << value << std::endl; }; incr_value(); print_value(); return 0; } ```