PHP: check if posted variable exists or assign null value
conditional-operator, php
Solution
Yes, that's an acceptable way of setting default values.
An alternative, introduced in PHP 5.3, is to omit the middle argument of your ternary expression:
$mycheck = $_POST['value'] ?: 0;
However, this will likely throw notices for trying to access an array with a non-existant key if `$_POST['value']` isn't set. Therefore your original method is more-accepted.
Problem
This can be done in Javascript with isNAN instead of !isset. Using the example below - both forms post to my script, one without a value and one with a value. Is the below code a correct way to do this in PHP to assign a value if the post var is not present? $mycheck = !isset($_POST['value']) ? 0 : $_POST['value']; ``` <? if($_POST) : $mycheck = !isset($_POST['value']) ? 0 : $_POST['value']; echo $mycheck; endif; ?> <!-- send value--> <form action="" method="post"> <select name="value"> <option value="0">0</option> <option value="5">5</option> </select> <input type="submit" name="submit"> </form> <!-- doesn't send value--> <form action="" method="post"> <input name="different_var"> <input type="submit" name="submit"> </form> ```